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MATH SOLVE
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BE RIGHT! PLEASE! And fast!
4 months ago
Q:
BE RIGHT! PLEASE! And fast!
Accepted Solution
A:
Answer:3k^3 + k^2 - 4kStep-by-step explanation:k * 3k^2 = 3k^3k * k = k^2k * -4 = -4k3k^3 + k^2 - 4k