HELP PLEASEThe ceiling of Katie’s living room is a square that is 12 ft long on each side. To decorate for a party, she plans to hang crepe paper around the perimeter of the ceiling and then from each corner to the opposite corner. Katie can buy rolls that each contain 10 ft of crepe paper. What is the minimum number of rolls she should buy? Show work.

Answer:The minimum number of rolls to buy is 9Step-by-step explanation:step 1Find the perimeter of the ceiling of Katie’s living roomThe perimeter of a square is equal to[tex]P=4b[/tex]where b is the length side of the squarewe have [tex]b=12\ ft[/tex]so[tex]P=4(12)=48\ ft[/tex]step 2Find the length side of the diagonals  of the ceilingApplying Pythagoras theorem[tex]d=\sqrt{12^{2} +12^{2}}\\ \\d=\sqrt{288}=16.97\ ft[/tex]step 3Find the total crepe paper neededSum the perimeter plus two times the length side of the diagonal[tex]48\ ft+2*(16.97\ ft)=81.94\ ft[/tex]step 4Find the number of rolls neededwe know thatEach roll contain 10 ft of crepe paperso[tex]81.94/10=8.19\ rolls[/tex]Round up[tex]8.19=9\ rolls[/tex]The minimum number of rolls to buy is 9