What are the zeros of the polynomial function f(x)=x^3-2x^2-8x? HELP NEEDED !!!! read closely!!!A. -2,4B. -2,0,4C. -4,2D. -4,0.2

Answer: -2, 0, 4Set the equation equal to zero.x³ - 2x² - 8x = 0Factor out x in the equation, since all the terms (x³, -2x², and -8x) are divisible by x. You can check your accuracy using the Distributive Property. x(x² - 2x - 8) = 0Factor out the polynomial. To do this, find two numbers that multiply to get the last term, -8, and add together to get the middle term, -2. In this case, those two numbers are -4 and 2 (-4 × 2 = -8 and -4 + 2 = -2). Don't forget about the x that was factored out before!x(x - 4)(x + 2) = 0Set each factor equal to zero and solve for x. The factors in the equation are x, (x - 4), and (x + 2).x = 0(x - 4) = 0         x = 4(x + 2) = 0           x = -2The zeros of the polynomial function are -2, 0, and 4.