Find the perimeter of the polygon with the vertices X(−1, 3), Y(3, 0), and Z(−1,−2). Round your answer to the nearest hundredth

Answer:The perimeter of the polygon is [tex]P=14.47\ units[/tex]Step-by-step explanation:we know thatThe perimeter is the sum of the length sides of the polygonIn this problemP=XY+YZ+XZthe formula to calculate the distance between two points is equal to [tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex] step 1 Find the distance XYwe haveX(−1, 3), Y(3, 0)substitute[tex]d=\sqrt{(0-3)^{2}+(3+1)^{2}}[/tex] [tex]d=\sqrt{25}[/tex] [tex]dXY=5\ units[/tex] step 2Find the distance YZwe have Y(3, 0), Z(−1,−2)substitute[tex]d=\sqrt{(-2-0)^{2}+(-1-3)^{2}}[/tex] [tex]d=\sqrt{20}[/tex] [tex]dYZ=4.47\ units[/tex] step 3Find the distance XZwe haveX(−1, 3), Z(−1,−2)substitute[tex]d=\sqrt{(-2-3)^{2}+(-1+1)^{2}}[/tex] [tex]d=\sqrt{25}[/tex] [tex]dXZ=5\ units[/tex] step 4 Find the perimeterP=XY+YZ+XZ[tex]P=5+4.47+5=14.47\ units[/tex]